196-y=y^2+28y+196

Solution for 196-y=y^2+28y+196 equation:

196-y=y^2+28y+196

We move all terms to the left:

196-y-(y^2+28y+196)=0

We add all the numbers together, and all the variables

-1y-(y^2+28y+196)+196=0

We get rid of parentheses

-y^2-1y-28y-196+196=0

We add all the numbers together, and all the variables

-1y^2-29y=0

a = -1; b = -29; c = 0;
Δ = b2-4ac
Δ = -292-4·(-1)·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-29}{2*-1}=\frac{0}{-2}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+29}{2*-1}=\frac{58}{-2}
=-29
$